 | Abel Flint - 1818 - عدد الصفحات: 184
...40' 23 20 1 95 00 48 20 CASE IV. y Tht three Sides given to find the Angles. Fig. 50. The solution of this CASE depends on the following PROPOSITION....half the Sum of the Segments, that is to half the krigth of the longest Side will give the greatest Segment ; and this half Difference subtracted from... | |
 | Charles Hutton - 1818 - عدد الصفحات: 646
...right-angled triangles : then the proportion will be, As , As the base, or sums of the segments, 1s to the sum of the other two sides ; ' So is the difference of those sides, To the diff. of the segments of the base. Then take half this difference of the segments,... | |
 | William Nicholson - 1821 - عدد الصفحات: 356
...986786 To the side DC required 144.8 2.16U76 .Axiom If. In any plane triangle, as the base, or greater side, is to the sum of the other two sides ; so is the difference of the sides to the difference of the segments of the base, made by a perpendicular let fall from the... | |
 | William Nicholson - 1821 - عدد الصفحات: 356
...2.03743 9-99116 To the side DC required 144.8 Aaeiom IV. In any plane triangle, as the base, or greater side, is to the sum of the other two sides ; so is the difference of the sides to the difference of the segments of the base, made by a perpendicular let fall from the... | |
 | Charles Hutton - 1822 - عدد الصفحات: 616
...into two right-angled triangles : then the proportion will be. As the base, or sums of the segments, Is to the sum of the other two sides ; So is the difference of those sides, To the diff. of the segments of the base. Then take half this difference of ihe segments,... | |
 | Edward Riddle - 1824 - عدد الصفحات: 572
...appropriate analogy in the first case. 3. When the three sides are given to find the angles. As the base, or longest side, is to the sum of the other two sides, so is the difference of those sides to the difference of the segments of the base, made by a perpendicular from the opposite... | |
 | Abel Flint - 1825 - عدد الصفحات: 252
...TRIGONOMETRY. CASE IV. The three Sides given to find the Angles. Fig. 50. Fig. 50. A. 105 B 2J The solution of this CASE depends on the following PROPOSITION....half the length of the longest Side, will give the greatest Segment ; and this half difference subtracted from the half sum will be the lesser Segment.... | |
 | Abel Flint - 1830 - عدد الصفحات: 322
...given tojlnd the angles. Fig. 49. The solution of this CASE depends on the following PROPOSITION. Itf EVERY PLANE TRIANGLE, AS THE LONGEST SIDE IS TO THE...half the length of the longest side, will give the greatest segment ; and this half difference subtracted from the half sum will be the lesser segment.... | |
 | Tobias Ostrander - 1833 - عدد الصفحات: 172
...angles, or the diameter of a circle circumscribing the triangle. Rule—As the whole length of the base is to the sum of the other two sides, so is the difference of those sides to the difference of the segments of the base; half the said difference added to half... | |
 | James Hann, Isaac Dodds - 1833 - عدد الصفحات: 234
...planes 50 inches ; required their common height, and the ratio of the weights. Rule. — As the base or longest side is to the sum of the other two sides, so is their difference to the difference of the segments of the base. And half the difference of the segments,... | |
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As the base or sum of the segments Is to the sum of the other two sides, So is the difference of those sides To the difference of the segments of the base. 
