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" ABCD (fig- 64), the breadth or perpendicular distance of either two opposite sides, as CP, is equal to the product of the corresponding oblique side CB by the sine of the angle of the parallelogram, radius being unity ((Trig. 30). Hence, the area of a... "
An Elementary Treatise on the Application of Trigonomentry to Orthographic ... - الصفحة 88
بواسطة John Farrar - 1833 - عدد الصفحات: 155
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An Elementary Treatise on the Application of Trigonometry: To Orthographic ...

John Farrar - 1822 - عدد الصفحات: 270
...the product of any two contiguous sides. 64. if the parallelogram be oblique.angled, as ABCD (Jig. 64), the breadth or perpendicular distance of either...radius being unity. Given AB = 59 chains 80 links, or 59,80ch., AC = 37,05 ch., and A = 90°, we have 59,8 x 37,05 x 1 = 2215,59 square chains = 22155900...

An Elementary Treatise on the Application of Trigonometry to Orthographic ...

John Farrar - 1822 - عدد الصفحات: 244
...product of any two contiguous sides. Fig. 64. If the parallelogram be oblique-angled, as ABCD (Jig. 64), the breadth or perpendicular distance of either...radius being unity. Given AB = 59 chains 80 links, or 59,80ch., AC = 37,05 ch., and A — 90°, we have 59,8 x 37,05 X 1 = 2215,59 square chains = 2:2155900...

An Elementary Treatise on the Application of Trigonomentry to Orthographic ...

John Farrar - 1833 - عدد الصفحات: 274
...supplements of each other (Geom. 64). The sines of all the angles therefore are equal to each other. product of the length by the breadth is the product...= 37,05 ch., and A = 90°, we have 59,8 X 37,05 X 1 = 2215,59 square chains = 22155900 square links. Now, since 10 square chains, 100000 square links,...

An Elementary Treatise of the Application of Trigonometry to Orthographic ...

John Farrar - 1840 - عدد الصفحات: 270
...product of any two contiguous sides. Fig. 64. If the parallelogram be oblique-angled, as AB CD (Jig. 64), the breadth or perpendicular distance of either...= 37,05 ch., and A = 90°, we have 59,8 X 37,05 X 1 = 2215,59 square chains = 22155900 square links. Now, since 10 square chains, 100000 square links,...

Elements of Plane Geometry: For the Use of Schools

Nicholas Tillinghast - 1844 - عدد الصفحات: 110
...Every parallelogram is equivalent to a rectangle which has an equal base and equal altitude. Cor. 2. Hence the area of a parallelogram is equal to the product of its base by its altitude (Prop. Cor. 3. Hence parallelograms of equal altitudes, are m proportion to...

Elements of geometry and mensuration

Thomas Lund - 1854 - عدد الصفحات: 522
...measure of the parallelogram ABCD=ABxBE = the base*. the height, as it is usually stated. In other words the area of a parallelogram is equal to the product of any one side and the perpendicular distance of that side from the opposite side. In any proposed case,...

A Compendious Course of Mathematics, theoretical and practical

John Radford YOUNG - 1855 - عدد الصفحات: 218
...parallelogram, and CE its altitude ; then, in the right-angled triangle AEC, we shall have _^* BO that the area of a parallelogram is equal to the product of any two adjacent sides multiplied by the sine of the angle between them. The trouble of finding the perpendicular...

The Complete Arithmetic: Oral and Written

Henry Bartlett Maglathlin - 1881 - عدد الصفحات: 418
...diagram that the rhombus ABCD is equal to the rectangle EBCF of the same base and altitude (Art. 218). Hence, The area of a parallelogram is equal to the product of the base and altitude. 9. What is the area of a parallelogram whose base is 36 feet and altitude 15...

The Competitor, المجلدات 3-4

1883 - عدد الصفحات: 248
...ABC = -ft and (1.) p = b sin A, which substitute for p, be sin A ac sin B ab sin C area of ABO = 2 Hence, the area of a parallelogram is equal to the product of two adjacent sides into the sine of the angle between them. Also, since the sine of an angle is equal...

Elements of Analytic Geometry

Joseph Johnston Hardy - 1897 - عدد الصفحات: 398
...cos A sin B. 14. The sides of a triangle are proportional to the sines of the opposite angles. 15. The area of a parallelogram is equal to the product of any two adjacent sides by the sine of the included angle. 16. In quadrant 2 the sine and cosecant only are...




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