 | Charles Hutton - 1811 - عدد الصفحات: 404
...c, the measure of ACE, supposing there to be • known АРБ = p, UPC = p, CP =: d, BC = L, AC = R. Since the exterior angle of a triangle is equal to the sum of the two interior opposite angles (th. 16 Geom.), we have, with respect to the triangle IAP, AIB = p... | |
 | Charles Hutton - 1812 - عدد الصفحات: 624
...to find c, the measure of ACB, supposing there to be known APB = r, BPC =fi, CP = d, BC = L, AC = R. Since the exterior angle of a triangle is equal to the sum of the two interior opposite angles (th. 1 6 Geom.), we have, •with respect to the triangle IAP, AIB... | |
 | John Gummere - 1814 - عدد الصفحات: 398
...took the angle of elevation BAG = 26° 30'. Required the height of the tree. Calculation. 1. Because the exterior angle of a triangle is equal to the sum of the two interior and opposite ones, the angle BDC = DAC + ACD ; therefore ACD - BDC — DAG = 25°... | |
 | Olinthus Gregory - 1816 - عدد الصفحات: 276
...staof the centre of 'r the sutnmit of ;Ie APB : it is re* the measure of here to be known p, ce = d,BQ Since the exterior angle of a triangle is equal to the sum of the two interior opposite angles, we have, with respect to the triangle IAP, AIB = P + IAP; and with... | |
 | John Farrar - 1822 - عدد الصفحات: 270
...another distance CB = 60 feet in the same direction, and take the angle ABD = 23° 45'. Now, sinre the exterior angle of a triangle is equal to the sum of the interior opposite angles, we have that is 4l° — 23° 45' =17° 15'. Hence in the triangle BAC. As sin BAC= 17° 15' ......... 9,47209... | |
 | John Farrar - 1833 - عدد الصفحات: 274
...9,99224 to AB 2,122\4 And as sin D = radius 10,00000 is to AB 2,12244 so is sin B . . 53° 9,90235 to AD . . 105,89 2,02479 52. The height of an obelisk...the sum of the interior opposite angles, we have ACD — A&b = BAC. that is 41° — 23° 45' = 17° 15'. Hence in the triangle BAC ; Ass'mBAC . . 17°... | |
 | 1836 - عدد الصفحات: 502
...example, suppose it known that the angles at the base of an isosceles triangle are equal, and also that the exterior angle of a triangle is equal to the sum of the interior and opposite angles. Suppose it also indisputable, that if A and B be respectively double of C and... | |
 | Schoolmaster - 1836 - عدد الصفحات: 926
...example, suppose it known that the angles at the base ofan isosceles triangle are equal, and also that the exterior angle of a triangle is equal to the sum of the interior and opposite angles. Suppose it also indisputable, that if A and B he respectively double of C and... | |
 | John Farrar - 1840 - عدد الصفحات: 270
...then measure another distance CB = 60 feet in the same direction, and take the angle ABD = 23° 4S'. Now, since the exterior angle of a triangle is equal...the interior opposite angles, we have ACD — ABC - BAC. that is 41° — 23° 45' = 17° 1&. 34 Hence in the triangle BAC ; As sin BAG . . l1° 15'... | |
 | John Narrien - 1845 - عدد الصفحات: 484
...the angle s' EH is equal to twice the angle AFB or OAF, produce FB to K, and FA to M : then because the exterior angle of a triangle is equal to the sum of the interior and opposite angles (Euc. 32. 1.), the angle ABK = BAF + AFB; whence 2 ABK = 2 BAF +2 AFB: but the... | |
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To prove that the exterior angle of a triangle is equal to the sum of the two interior opposite angles (see fig. 
