...having discovered the demonstration of the 47th proposition of the first book of Euclid, viz. that in n right angled triangle the square of the hypothenuse is equal to the sum of the squares of the two other sides. Julius Capito/ linus relates, that when an Hecatomb was to be sacrificed,...

...differs 2 Minutes from the Angle as found by Logarithms, is that the Table of Logarithmic Sines, Sec. contained in this Book, is calculated only for every...Square of the Hypothenuse is equal to the Sum of the Squares of the two Legs. Hence, The Square of the given Leg being subtracted from the Square of the...

...referred to. 94. Other relations of the sine, tangent, Sic. may be derived from the proposition, that the square of the hypothenuse is equal to the sum of the squares of the perpendicular sides. (Euc. 47. I.) In the right angled triangles CBG, CAD, and CHF,...

...the third side may be found, without the aid of the trigonometrical tables, by the proposition, that the square of the hypothenuse is equal to the sum of the squares of the two perpendicular sides. (Euc. 47. 1.) If the legs be given, extracting the square root...

...arc AD B. 4. An angle IAD in a semi'circle is a right angle (EUCLID 31 ./III.) 5. In a right-angled triangle the square of the hypothenuse is equal to the sum of the squares of the other two sides, (EuctiD 47 «/"!.) see also Problem VI. 6. If a perpendicular be drawn...

...the nearest corresponding Dumber of Degrees and Minutes will be found to be 53° 8', the Angle ACB. Note. The reason why the Angle as found by Nat. Sines...Square of the Hypothenuse is equal to the Sum of the Squares of the two Legs. Hence, The Square of the given Leg being subtracted from the Square of the...

...observes: •;•• ,'.I asked the Japanese academician whether he was perfectly convinced that in a right angled triangle the square of the hypothenuse is equal to the squares of the other two sides ? He answered in the affirmative. I then asked how they were certain...

...which subtends the right angle. Euclid, lib. i. proposition 47, demonstrates, that in every rectilmear right angled triangle, the square of the hypothenuse is equal to the squares of both the other sides. This celebrated problem was discovered by Pythagoras, who is said...

...others ; for the three figures will be proportional to the squares of their homologous sides ; now the square of the hypothenuse is equal to the sum of the squares of the two other sides ; therefore, &c. THEOREM. 223. The parts of two chards which cut each...

...right-angled triangles, which are similar to the first triangle, and to one another. In every right-angled triangle, the square of the hypothenuse is equal to the sum of the squares of the other two sides; and, in general, any figure described on the hypothenuse is equal to...